I'm looking at the specs for the Kohler 14 kW RESA Generator, and it consumes 81 CFH of propane per hour to generate its full output of 14,000 Watts/Hr.

1 CFH = 2,500 BTU of LP/Propane (one source said 2,516)

81 CFH x 2,500 BTU's/CFH= 202,500 BTU's per hour of propane consumed by the generator at full output load of 14,000 Watts per hour

Propane has 96,500 BTU's per gallon (so it burns 2.1 gallons of propane per hour to deliver 14,000 watts/hr. of electricity)

14,000 Watts x 3.412 BTU's/Watt = 47,768 BTU's per hour equivalent delivered by the generator at full output

47,768 (BTU's equivalent out) / 202,500 (BTU's in) = 0.236

0.236 x 100 = 23.6% efficiency in converting propane into electricity for this generator

Overall that seems to be quite good. But am I calculating the correctly?