The BTUH ratings on both coal and wood stoves are not monitored or regulated, and are arbitrary (I.E. guesses more for advertising and marketing than for reality). Stoves are likely only at best generally "real world" capable of 50% of that without glowing red and wilting from the heat. And that is on the input side. On the output side they can only perhaps deliver about 35% of that. 160,000 x 0.35 = 56,000 BTUH output. That is easily enough to heat most average homes on the coldest day of the year, but yours is on the large side, so if it is not modern and well insulated that may not do it.
To put it into perspective, to achieve 160,000 BTUH input (BTU's per hour of input) would require burning about 33 pounds of seasoned hardwood wood per hour, or 13 pounds of anthracite coal per hour. And to sustain that for a single day would require the burning of 792 lbs. of wood or 312 lbs. of coal.
What really matters however is your homes heat loss calculation. That and proper heat distribution (which for a single stove is more often than not a very difficult task to accomplish). A heat loss calculation will tell you if 56,000 BTUH output is sufficient. But then you need to move the heat around so the home does not roast in one area and freeze in other areas. There are only perhaps 2 or 3 days a heating season when you will tax the homes heat loss requirements. On an average winter day you will need about 40% of "heat loss" BTUH output. For grins, lets assume a heat loss of 56,000 BTUH. 40% of 56,000 BTUH is 22,400 BTUH of output, which is the equivalent of burning about 4.6 lbs of seasoned hardwood per hour or 2.6 lbs. of coal per hour. 110 lbs of wood or 62 lbs. of coal would be your average daily requirement.
Moving heat around evenly is why I went with a coal boiler and hot water baseboards.